3[4x-4(x-3)]+1=16

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Solution for 3[4x-4(x-3)]+1=16 equation: 


Simplifying
3[4x + -4(x + -3)] + 1 = 16

Reorder the terms:
3[4x + -4(-3 + x)] + 1 = 16
3[4x + (-3 * -4 + x * -4)] + 1 = 16
3[4x + (12 + -4x)] + 1 = 16

Reorder the terms:
3[12 + 4x + -4x] + 1 = 16

Combine like terms: 4x + -4x = 0
3[12 + 0] + 1 = 16
3[12] + 1 = 16

Multiply 3 * 12
36 + 1 = 16

Combine like terms: 36 + 1 = 37
37 = 16

Solving
37 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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